Y = 2x ^ 2 + 3x-8'in tepe biçimi nedir?

Cevap:

Köşe formu $y = 2 {(x + \frac{3}{4})}^{2} - \frac{73}{8}$ $y = 2 (x + 3/4) ^ 2 - 73/8$

$y = 2 x^{2} + 3 x - 8 y a d a y = 2 (x^{2} + \frac{3}{2} x) - 8$ $y = 2x ^ 2 + 3x -8 ya da y = 2 (x ^ 2 + 3 / 2x) -8$ veya

$y = 2 (x^{2} + \frac{3}{2} x + {(\frac{3}{4})}^{2}) - 2 \cdot \frac{9}{16} - 8$ $y = 2 (x ^ 2 + 3 / 2x + (3/4) ^ 2) - 2 * 9 / 16-8$ veya

$y = 2 {(x + \frac{3}{4})}^{2} - \frac{9}{8} - 8$ $y = 2 (x + 3/4) ^ 2-9 / 8-8$ veya

$y = 2 {(x + \frac{3}{4})}^{2} - \frac{73}{8}$ $y = 2 (x + 3/4) ^ 2 - 73/8$

Köşe $(- \frac{3}{4}, - 9 \frac{1}{8})$ $(-3/4, -9 1/8)$

Köşe formu $y = 2 {(x + \frac{3}{4})}^{2} - \frac{73}{8}$ $y = 2 (x + 3/4) ^ 2 - 73/8$ Ans