F (x) = 3 ^ (x ^ 2-3x) 'nin tersi nedir?

F (x) = 3 ^ (x ^ 2-3x) 'nin tersi nedir?
Anonim

Cevap:

• y = 3/2 + -sqrt (log_3x + 9/4) #

Açıklama:

• y = 3 ^ (x ^ 2-3x) #

fiske # X # ve • y #.

#, X = 3 ^ (y ^ 2-3y) #

İçin çözün • y #.

# Log_3x = log_3 (3 ^ (y ^ 2-3y)) #

# Log_3x = y ^ 2-3y #

# Log_3x + 9/4 = y ^ 2-3y + 9/4 #

# Log_3x + 9/4 = (yo-3/2) ^ 2 #

# + - sqrt (log_3x + 9/4) = y 3/2 #

• y = 3/2 + -sqrt (log_3x + 9/4) #