X = -pi / 3'te f (x) = cscx + tanx-cotx ile normal olan çizginin denklemi nedir?

Cevap:

#y = - (3x) /14-2.53#

Açıklama:

# "Teğet": e / dx f (x) = f (x), #

# "Normal": - 1 / (f (x)) = - 1 / (d / dx cscx + tanx-cotx) = - 1 / (d / dx cscx + d / dx tanx - d / dx cotx) = - 1 / (- cscxcotx + iki ^ 2x + cSC ^ 2x) #

# -1 / (f (- pi / 3)) = - 1 / (- CSC (-pi / 3) yatağı (-pi / 3) + iki ^ 2 (-pi / 3) + CSC ^ 2 (- pi / 3)) = - 1 / (14/3) = - 3/14 #

• y = mx + c #

#f (a) Tma + c # =

#csc (-pi / 3) + tan (-pi / 3) -cot (-pi / 3) = - pi / 3 (-3/14) + c #

# C = CSC (-pi / 3) + tan (-pi / 3) -cot (-pi / 3) + pi / 3 (-3/14) #

# C = -2.53 #

#y = - (3x) /14-2.53#